2023-06-04 00:01:03 +00:00
|
|
|
# hexadecimal
|
|
|
|
|
|
|
|
the hexadecimal numeral system differs from the decimal system by having 16 digits rather than 10:
|
|
|
|
|
|
|
|
```
|
|
|
|
hex| decimal
|
|
|
|
---|---------
|
2023-06-04 00:02:01 +00:00
|
|
|
0 | 0
|
|
|
|
1 | 1
|
|
|
|
2 | 2
|
|
|
|
3 | 3
|
|
|
|
4 | 4
|
|
|
|
5 | 5
|
|
|
|
6 | 6
|
|
|
|
7 | 7
|
|
|
|
8 | 8
|
|
|
|
9 | 9
|
|
|
|
A | 10
|
|
|
|
B | 11
|
|
|
|
C | 12
|
|
|
|
D | 13
|
|
|
|
E | 14
|
|
|
|
F | 15
|
2023-06-04 00:01:03 +00:00
|
|
|
```
|
|
|
|
|
|
|
|
when there is more than one digit, these are multiplied by 16, 256, 4096 and so on rather than 10, 100, 1000:
|
|
|
|
|
|
|
|
```
|
|
|
|
hex | decimal
|
|
|
|
----|---------
|
2023-06-04 00:02:01 +00:00
|
|
|
00 | 0
|
|
|
|
04 | 4
|
|
|
|
08 | 8
|
|
|
|
0F | 15
|
|
|
|
10 | 16
|
|
|
|
11 | 17
|
|
|
|
12 | 18
|
|
|
|
13 | 19
|
|
|
|
20 | 32
|
|
|
|
30 | 48
|
|
|
|
40 | 64
|
2023-06-04 00:01:03 +00:00
|
|
|
```
|
|
|
|
|
|
|
|
# hex to decimal
|
|
|
|
|
|
|
|
for example, take hexadecimal number `AA`:
|
|
|
|
|
|
|
|
```
|
|
|
|
2nd digit -\ /- 1st digit
|
|
|
|
A A
|
|
|
|
16^1*10 = 16*10 = 160 + 10 = 170
|
|
|
|
```
|
|
|
|
|
|
|
|
now for hexadecimal number `4C5F`:
|
|
|
|
|
|
|
|
```
|
|
|
|
|
|
|
|
3rd digit -\ /- 2nd digit
|
|
|
|
4th digit -\ | | /- 1st digit
|
|
|
|
4 C 5 F
|
|
|
|
| | | |
|
|
|
|
| | | 15 = 15 = 15 +
|
|
|
|
| | \16^1*5 = 16 * 5 = 80
|
|
|
|
| \--- 16^2*12 = 256 * 12 = 3072
|
|
|
|
\--------- 16^3*4 = 4096 * 4 = 16384
|
|
|
|
-------
|
|
|
|
= 19551
|
|
|
|
```
|
|
|
|
|
|
|
|
# decimal to hex
|
|
|
|
|
|
|
|
if it's less than 16, just memorize the table at the top of this document.
|
|
|
|
|
|
|
|
otherwise find the power of 16 that is closest to the number you want to convert, but no larger than the number.
|
|
|
|
then divide, and take the remainder.
|
|
|
|
divide the remainder with the previous power of 16, until the divider is 1.
|
|
|
|
|
|
|
|
for example, for the decimal number `220`:
|
|
|
|
|
|
|
|
```
|
|
|
|
220 ÷ 16 = 13 (r = 12) D
|
|
|
|
12 ÷ 1 = 12 (stop here) C
|
|
|
|
|
|
|
|
= DC
|
|
|
|
```
|
|
|
|
|
|
|
|
now for decimal number `69420`:
|
|
|
|
|
|
|
|
```
|
|
|
|
69420 ÷ 65536 = 1 (r = 3884) 1
|
|
|
|
3884 ÷ 4096 = 0 (r = 3884) 0
|
|
|
|
3884 ÷ 256 = 15 (r = 44) F
|
|
|
|
44 ÷ 16 = 2 (r = 12) 2
|
|
|
|
12 ÷ 1 = 12 (stop here) C
|
|
|
|
|
|
|
|
= 10F2C
|
|
|
|
```
|