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[utils] Fix slicing of reversed LazyList

Closes #589
This commit is contained in:
pukkandan 2021-08-01 11:47:30 +05:30
parent eca330cb88
commit e0f2b4b47d
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2 changed files with 12 additions and 9 deletions

View file

@ -1537,8 +1537,11 @@ def test_LazyList(self):
self.assertEqual(LazyList(it).exhaust(), it)
self.assertEqual(LazyList(it)[5], it[5])
self.assertEqual(LazyList(it)[5:], it[5:])
self.assertEqual(LazyList(it)[:5], it[:5])
self.assertEqual(LazyList(it)[::2], it[::2])
self.assertEqual(LazyList(it)[1::2], it[1::2])
self.assertEqual(LazyList(it)[5::-1], it[5::-1])
self.assertEqual(LazyList(it)[6:2:-2], it[6:2:-2])
self.assertEqual(LazyList(it)[::-1], it[::-1])
@ -1550,6 +1553,7 @@ def test_LazyList(self):
self.assertEqual(list(LazyList(it).reverse()), it[::-1])
self.assertEqual(list(LazyList(it).reverse()[1:3:7]), it[::-1][1:3:7])
self.assertEqual(list(LazyList(it).reverse()[::-1]), it)
def test_LazyList_laziness(self):

View file

@ -3993,28 +3993,27 @@ def exhaust(self):
@staticmethod
def __reverse_index(x):
return -(x + 1)
return None if x is None else -(x + 1)
def __getitem__(self, idx):
if isinstance(idx, slice):
step = idx.step or 1
start = idx.start if idx.start is not None else 0 if step > 0 else -1
stop = idx.stop if idx.stop is not None else -1 if step > 0 else 0
if self.__reversed:
(start, stop), step = map(self.__reverse_index, (start, stop)), -step
idx = slice(start, stop, step)
idx = slice(self.__reverse_index(idx.start), self.__reverse_index(idx.stop), -(idx.step or 1))
start, stop, step = idx.start, idx.stop, idx.step or 1
elif isinstance(idx, int):
if self.__reversed:
idx = self.__reverse_index(idx)
start = stop = idx
start, stop, step = idx, idx, 0
else:
raise TypeError('indices must be integers or slices')
if start < 0 or stop < 0:
if ((start or 0) < 0 or (stop or 0) < 0
or (start is None and step < 0)
or (stop is None and step > 0)):
# We need to consume the entire iterable to be able to slice from the end
# Obviously, never use this with infinite iterables
return self.__exhaust()[idx]
n = max(start, stop) - len(self.__cache) + 1
n = max(start or 0, stop or 0) - len(self.__cache) + 1
if n > 0:
self.__cache.extend(itertools.islice(self.__iterable, n))
return self.__cache[idx]