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In C, in order to use a plan, one normally calls fftw_execute
,
which executes the plan to perform the transform on the input/output
arrays passed when the plan was created (see Using Plans). The
corresponding subroutine call in modern Fortran is:
call fftw_execute(plan)
However, we have had reports that this causes problems with some
recent optimizing Fortran compilers. The problem is, because the
input/output arrays are not passed as explicit arguments to
fftw_execute
, the semantics of Fortran (unlike C) allow the
compiler to assume that the input/output arrays are not changed by
fftw_execute
. As a consequence, certain compilers end up
repositioning the call to fftw_execute
, assuming incorrectly
that it does nothing to the arrays.
There are various workarounds to this, but the safest and simplest
thing is to not use fftw_execute
in Fortran. Instead, use the
functions described in New-array Execute Functions, which take
the input/output arrays as explicit arguments. For example, if the
plan is for a complex-data DFT and was created for the arrays
in
and out
, you would do:
call fftw_execute_dft(plan, in, out)
There are a few things to be careful of, however:
fftw_execute_dft
, Real-input (r2c) DFT plans should use use
fftw_execute_dft_r2c
, and real-output (c2r) DFT plans should
use fftw_execute_dft_c2r
. The various r2r plans should use
fftw_execute_r2r
. Fortunately, if you use the wrong one you
will get a compile-time type-mismatch error (unlike legacy Fortran).
FFTW_UNALIGNED
flag when creating the
plan, in which case the plan does not depend on the alignment, but
this may sacrifice substantial performance on architectures (like x86)
with SIMD instructions (see SIMD alignment and fftw_malloc).
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